Tugas Himpunan 1
Jika P,Q,R adalah himpunan ,buktikan bahwa
(PᴗQ)ᴖ(PcᴖR)c = Pᴗ(QcᴗR)c
Pembuktian
Pembuktian
1
Diketahui :
P={1,3,4,6,7} S={1,2,3,4,5,6,7,8,10,11,13}
Q={2,3,4,5,8,10}
R={1,6,10,11,13}
Jawab :
PᴗQ ={1,2,3,4,5,6,7,8,9,10} QC ={1,6,7,11,13}
PC ={1,2,3,4,5,6,7,8} QCᴗR ={1,6,7,10,11,13}
PCᴖR ={10,11,13} (QCᴗR)C ={2,3,4,5,8}
(PCᴖR)C ={1,2,3,4,5,6,7,8}
(PᴗQ)ᴖ(PCᴖR)C ={1,2,3,4,5,6,7,8} Pᴗ(QCᴗR)C ={1,2,3,4,5,6,7,8}
Pembuktian 2
Diketahui :
P={a,b,d,h,i,k} S={a,b,c,d,e,f,g,h,i,j,k}
Q={b,c,e,f,h}
R={c,d,g,h,j}
Jawab :
PᴗQ ={a,b,c,d,e,f,h,i,k} Qc ={a,d,g,i,j,k}
Pc ={c,f,g,j} QcᴗR ={a,c,d,g,h,I,j,k}
PcᴖR ={c,g,j} (QcᴗR)c ={b,e,f}
(PcᴖR)c ={a,b,d,e,f,h,i,k}
(PᴗQ)ᴖ(PcᴖR)c ={a,b,d,e,f,h,i,k} Pᴗ(QcᴗR)c ={a,b,d,e,f,h,I,k}
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